- #1

- 102

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If

*l*has parametric equations

x = 5-3t

y = -2+t

z = 1+9t

find parametic equations for the line through P(-6,4,-3) that is parallel to

*l*.

So, my question is this: for the two lines to be parallel, they have to have the same direction vector right? In this case, <-3, 1, 9>. So if I were to find the parallel line to

*l*, it would be:

x = -6-3s

y = 4+s

z = -3+9s

Thanks!!